Base | Representation |
---|---|
bin | 11010101101100111… |
… | …01110000000100101 |
3 | 1101000110200112111221 |
4 | 31112303232000211 |
5 | 213332333102021 |
6 | 10331023500341 |
7 | 1015251020011 |
oct | 152663560045 |
9 | 41013615457 |
10 | 14341300261 |
11 | 609a321172 |
12 | 2942a576b1 |
13 | 147723a2b2 |
14 | 9a095b541 |
15 | 58e09e241 |
hex | 356cee025 |
14341300261 has 2 divisors, whose sum is σ = 14341300262. Its totient is φ = 14341300260.
The previous prime is 14341300199. The next prime is 14341300271. The reversal of 14341300261 is 16200314341.
14341300261 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14134832100 + 206468161 = 118890^2 + 14369^2 .
It is a cyclic number.
It is not a de Polignac number, because 14341300261 - 223 = 14332911653 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14341300271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170650130 + 7170650131.
It is an arithmetic number, because the mean of its divisors is an integer number (7170650131).
Almost surely, 214341300261 is an apocalyptic number.
It is an amenable number.
14341300261 is a deficient number, since it is larger than the sum of its proper divisors (1).
14341300261 is an equidigital number, since it uses as much as digits as its factorization.
14341300261 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
The spelling of 14341300261 in words is "fourteen billion, three hundred forty-one million, three hundred thousand, two hundred sixty-one".
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