Base | Representation |
---|---|
bin | 1000010110010000011… |
… | …0011110110000001111 |
3 | 111201011201111120121121 |
4 | 2011210012132300033 |
5 | 4322202303404244 |
6 | 145514433341411 |
7 | 13234626200242 |
oct | 2054406366017 |
9 | 451151446547 |
10 | 143413341199 |
11 | 55904101987 |
12 | 23964a07867 |
13 | 106a6aa940b |
14 | 6d26aad259 |
15 | 3ae5711c84 |
hex | 216419ec0f |
143413341199 has 2 divisors, whose sum is σ = 143413341200. Its totient is φ = 143413341198.
The previous prime is 143413341193. The next prime is 143413341233. The reversal of 143413341199 is 991143314341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 143413341199 - 229 = 142876470287 is a prime.
It is a super-3 number, since 3×1434133411993 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143413341193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71706670599 + 71706670600.
It is an arithmetic number, because the mean of its divisors is an integer number (71706670600).
Almost surely, 2143413341199 is an apocalyptic number.
143413341199 is a deficient number, since it is larger than the sum of its proper divisors (1).
143413341199 is an equidigital number, since it uses as much as digits as its factorization.
143413341199 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 139968, while the sum is 43.
The spelling of 143413341199 in words is "one hundred forty-three billion, four hundred thirteen million, three hundred forty-one thousand, one hundred ninety-nine".
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