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14341441321055 = 516931694204527
BaseRepresentation
bin1101000010110010000010…
…0000111111100001011111
31212210000202201000012210102
43100230200200333201133
53334432232434233210
650300211151331315
73010064166606062
oct320544040774137
955700681005712
1014341441321055
11462a197821852
121737573820b3b
138005136207b4
143781b53688d9
1519d0c189bea5
hexd0b2083f85f

14341441321055 has 8 divisors (see below), whose sum is σ = 17219894822592. Its totient is φ = 11466376231968.

The previous prime is 14341441321043. The next prime is 14341441321091. The reversal of 14341441321055 is 55012314414341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14341441321055 - 26 = 14341441320991 is a prime.

It is a super-4 number, since 4×143414413210554 (a number of 54 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 847093799 + ... + 847110728.

It is an arithmetic number, because the mean of its divisors is an integer number (2152486852824).

Almost surely, 214341441321055 is an apocalyptic number.

14341441321055 is a deficient number, since it is larger than the sum of its proper divisors (2878453501537).

14341441321055 is a wasteful number, since it uses less digits than its factorization.

14341441321055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1694206225.

The product of its (nonzero) digits is 115200, while the sum is 38.

Adding to 14341441321055 its reverse (55012314414341), we get a palindrome (69353755735396).

The spelling of 14341441321055 in words is "fourteen trillion, three hundred forty-one billion, four hundred forty-one million, three hundred twenty-one thousand, fifty-five".

Divisors: 1 5 1693 8465 1694204527 8471022635 2868288264211 14341441321055