Base | Representation |
---|---|
bin | 1101000010110010000010… |
… | …0000111111100001011111 |
3 | 1212210000202201000012210102 |
4 | 3100230200200333201133 |
5 | 3334432232434233210 |
6 | 50300211151331315 |
7 | 3010064166606062 |
oct | 320544040774137 |
9 | 55700681005712 |
10 | 14341441321055 |
11 | 462a197821852 |
12 | 1737573820b3b |
13 | 8005136207b4 |
14 | 3781b53688d9 |
15 | 19d0c189bea5 |
hex | d0b2083f85f |
14341441321055 has 8 divisors (see below), whose sum is σ = 17219894822592. Its totient is φ = 11466376231968.
The previous prime is 14341441321043. The next prime is 14341441321091. The reversal of 14341441321055 is 55012314414341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14341441321055 - 26 = 14341441320991 is a prime.
It is a super-4 number, since 4×143414413210554 (a number of 54 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 847093799 + ... + 847110728.
It is an arithmetic number, because the mean of its divisors is an integer number (2152486852824).
Almost surely, 214341441321055 is an apocalyptic number.
14341441321055 is a deficient number, since it is larger than the sum of its proper divisors (2878453501537).
14341441321055 is a wasteful number, since it uses less digits than its factorization.
14341441321055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1694206225.
The product of its (nonzero) digits is 115200, while the sum is 38.
Adding to 14341441321055 its reverse (55012314414341), we get a palindrome (69353755735396).
The spelling of 14341441321055 in words is "fourteen trillion, three hundred forty-one billion, four hundred forty-one million, three hundred twenty-one thousand, fifty-five".
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