14342102530055 has 8 divisors (see below), whose sum is σ = 17240770004400. Its totient is φ = 11453517378496.

The previous prime is 14342102530043. The next prime is 14342102530117. The reversal of 14342102530055 is 55003520124341.

14342102530055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14342102530055 - 2¹⁶ = 14342102464519 is a prime.

It is a super-3 number, since 3×14342102530055³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 14342102529997 and 14342102530024.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2520577565 + ... + 2520583254.

It is an arithmetic number, because the mean of its divisors is an integer number (2155096250550).

Almost surely, 2^{14342102530055} is an apocalyptic number.

14342102530055 is a deficient number, since it is larger than the sum of its proper divisors (2898667474345).

14342102530055 is an equidigital number, since it uses as much as digits as its factorization.

14342102530055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5041161393.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 14342102530055 its reverse (55003520124341), we get a palindrome (69345622654396).

The spelling of 14342102530055 in words is "fourteen trillion, three hundred forty-two billion, one hundred two million, five hundred thirty thousand, fifty-five".