Base | Representation |
---|---|
bin | 1101000010110100100011… |
… | …1111001100000011010111 |
3 | 1212210002112000200012120002 |
4 | 3100231020333030003113 |
5 | 3334440130300402320 |
6 | 50300402405001515 |
7 | 3010120053213305 |
oct | 320551077140327 |
9 | 55702460605502 |
10 | 14342120325335 |
11 | 462a506030810 |
12 | 17377230b329b |
13 | 8005c11bb48a |
14 | 37823b5d9275 |
15 | 19d1112c3675 |
hex | d0b48fcc0d7 |
14342120325335 has 32 divisors (see below), whose sum is σ = 18916611436800. Its totient is φ = 10352088149760.
The previous prime is 14342120325317. The next prime is 14342120325349. The reversal of 14342120325335 is 53352302124341.
14342120325335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14342120325335 - 214 = 14342120308951 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 22382072 + ... + 23013938.
It is an arithmetic number, because the mean of its divisors is an integer number (591144107400).
Almost surely, 214342120325335 is an apocalyptic number.
14342120325335 is a deficient number, since it is larger than the sum of its proper divisors (4574491111465).
14342120325335 is a wasteful number, since it uses less digits than its factorization.
14342120325335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 634991.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 14342120325335 its reverse (53352302124341), we get a palindrome (67694422449676).
The spelling of 14342120325335 in words is "fourteen trillion, three hundred forty-two billion, one hundred twenty million, three hundred twenty-five thousand, three hundred thirty-five".
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