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14342215023053 is a prime number
BaseRepresentation
bin1101000010110100111010…
…1000011011100111001101
31212210002202121212100101222
43100231032220123213031
53334440324021214203
650300420030413125
73010122313143041
oct320551650334715
955702677770358
1014342215023053
11462a554530595
12173774a9611a5
138006079c6728
1437824a00a021
1519d11977c038
hexd0b4ea1b9cd

14342215023053 has 2 divisors, whose sum is σ = 14342215023054. Its totient is φ = 14342215023052.

The previous prime is 14342215023049. The next prime is 14342215023067. The reversal of 14342215023053 is 35032051224341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9755858692969 + 4586356330084 = 3123437^2 + 2141578^2 .

It is a cyclic number.

It is not a de Polignac number, because 14342215023053 - 22 = 14342215023049 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14342215023013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171107511526 + 7171107511527.

It is an arithmetic number, because the mean of its divisors is an integer number (7171107511527).

Almost surely, 214342215023053 is an apocalyptic number.

It is an amenable number.

14342215023053 is a deficient number, since it is larger than the sum of its proper divisors (1).

14342215023053 is an equidigital number, since it uses as much as digits as its factorization.

14342215023053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 14342215023053 its reverse (35032051224341), we get a palindrome (49374266247394).

The spelling of 14342215023053 in words is "fourteen trillion, three hundred forty-two billion, two hundred fifteen million, twenty-three thousand, fifty-three".