14342255151053 has 4 divisors (see below), whose sum is σ = 15185917218780. Its totient is φ = 13498593083328.

The previous prime is 14342255150987. The next prime is 14342255151061. The reversal of 14342255151053 is 35015155224341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11889407402404 + 2452847748649 = 3448102^2 + 1566157^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14342255151053 is a prime.

It is a super-3 number, since 3×14342255151053³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14342255151053.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14342255151953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 421831033838 + ... + 421831033871.

It is an arithmetic number, because the mean of its divisors is an integer number (3796479304695).

Almost surely, 2^{14342255151053} is an apocalyptic number.

It is an amenable number.

14342255151053 is a deficient number, since it is larger than the sum of its proper divisors (843662067727).

14342255151053 is an equidigital number, since it uses as much as digits as its factorization.

14342255151053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 843662067726.

The product of its (nonzero) digits is 360000, while the sum is 41.

The spelling of 14342255151053 in words is "fourteen trillion, three hundred forty-two billion, two hundred fifty-five million, one hundred fifty-one thousand, fifty-three".