Base | Representation |
---|---|
bin | 1101000010111000011000… |
… | …0001011010110011111110 |
3 | 1212210012011101111112111211 |
4 | 3100232012001122303332 |
5 | 3334444224421222004 |
6 | 50301052144435034 |
7 | 3010154326062241 |
oct | 320560601326376 |
9 | 55705141445454 |
10 | 14343144320254 |
11 | 462a991053302 |
12 | 173796a018a7a |
13 | 8007253aa229 |
14 | 3782d75d1258 |
15 | 19d171144504 |
hex | d0b8605acfe |
14343144320254 has 8 divisors (see below), whose sum is σ = 21523150324368. Its totient is φ = 7168760878800.
The previous prime is 14343144320161. The next prime is 14343144320261. The reversal of 14343144320254 is 45202344134341.
14343144320254 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1405634287 + ... + 1405644490.
It is an arithmetic number, because the mean of its divisors is an integer number (2690393790546).
Almost surely, 214343144320254 is an apocalyptic number.
14343144320254 is a deficient number, since it is larger than the sum of its proper divisors (7180006004114).
14343144320254 is a wasteful number, since it uses less digits than its factorization.
14343144320254 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2811281330.
The product of its (nonzero) digits is 552960, while the sum is 40.
Adding to 14343144320254 its reverse (45202344134341), we get a palindrome (59545488454595).
The spelling of 14343144320254 in words is "fourteen trillion, three hundred forty-three billion, one hundred forty-four million, three hundred twenty thousand, two hundred fifty-four".
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