Base | Representation |
---|---|
bin | 1101000010111000011000… |
… | …0001011010110011111111 |
3 | 1212210012011101111112111212 |
4 | 3100232012001122303333 |
5 | 3334444224421222010 |
6 | 50301052144435035 |
7 | 3010154326062242 |
oct | 320560601326377 |
9 | 55705141445455 |
10 | 14343144320255 |
11 | 462a991053303 |
12 | 173796a018a7b |
13 | 8007253aa22a |
14 | 3782d75d1259 |
15 | 19d171144505 |
hex | d0b8605acff |
14343144320255 has 8 divisors (see below), whose sum is σ = 18117655983600. Its totient is φ = 10870593590016.
The previous prime is 14343144320161. The next prime is 14343144320261. The reversal of 14343144320255 is 55202344134341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14343144320255 - 220 = 14343143271679 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75490233170 + ... + 75490233359.
It is an arithmetic number, because the mean of its divisors is an integer number (2264706997950).
Almost surely, 214343144320255 is an apocalyptic number.
14343144320255 is a deficient number, since it is larger than the sum of its proper divisors (3774511663345).
14343144320255 is a wasteful number, since it uses less digits than its factorization.
14343144320255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 150980466553.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 14343144320255 its reverse (55202344134341), we get a palindrome (69545488454596).
The spelling of 14343144320255 in words is "fourteen trillion, three hundred forty-three billion, one hundred forty-four million, three hundred twenty thousand, two hundred fifty-five".
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