Base | Representation |
---|---|
bin | 11010101101110110… |
… | …10110010101011101 |
3 | 1101000121110011020211 |
4 | 31112323112111131 |
5 | 213333341103240 |
6 | 10331134412421 |
7 | 1015304020315 |
oct | 152673262535 |
9 | 41017404224 |
10 | 14343300445 |
11 | 60a0467a11 |
12 | 2943661111 |
13 | 147778a836 |
14 | 9a0d1c445 |
15 | 58e346bea |
hex | 356ed655d |
14343300445 has 4 divisors (see below), whose sum is σ = 17211960540. Its totient is φ = 11474640352.
The previous prime is 14343300427. The next prime is 14343300473. The reversal of 14343300445 is 54400334341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10991006244 + 3352294201 = 104838^2 + 57899^2 .
It is a cyclic number.
It is not a de Polignac number, because 14343300445 - 29 = 14343299933 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1434330040 + ... + 1434330049.
It is an arithmetic number, because the mean of its divisors is an integer number (4302990135).
Almost surely, 214343300445 is an apocalyptic number.
It is an amenable number.
14343300445 is a deficient number, since it is larger than the sum of its proper divisors (2868660095).
14343300445 is an equidigital number, since it uses as much as digits as its factorization.
14343300445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2868660094.
The product of its (nonzero) digits is 34560, while the sum is 31.
Adding to 14343300445 its reverse (54400334341), we get a palindrome (68743634786).
The spelling of 14343300445 in words is "fourteen billion, three hundred forty-three million, three hundred thousand, four hundred forty-five".
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