14343304121 has 2 divisors, whose sum is σ = 14343304122. Its totient is φ = 14343304120.

The previous prime is 14343304111. The next prime is 14343304123. The reversal of 14343304121 is 12140334341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10133240896 + 4210063225 = 100664^2 + 64885^2 .

It is a cyclic number.

It is not a de Polignac number, because 14343304121 - 2²² = 14339109817 is a prime.

It is a Sophie Germain prime.

Together with 14343304123, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (14343304123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171652060 + 7171652061.

It is an arithmetic number, because the mean of its divisors is an integer number (7171652061).

Almost surely, 2^14343304121 is an apocalyptic number.

It is an amenable number.

14343304121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14343304121 is an equidigital number, since it uses as much as digits as its factorization.

14343304121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 14343304121 its reverse (12140334341), we get a palindrome (26483638462).

The spelling of 14343304121 in words is "fourteen billion, three hundred forty-three million, three hundred four thousand, one hundred twenty-one".