Base | Representation |
---|---|
bin | 11010101101110111… |
… | …01111011100101011 |
3 | 1101000121122101100112 |
4 | 31112323233130223 |
5 | 213333402401212 |
6 | 10331140524535 |
7 | 1015304626232 |
oct | 152673573453 |
9 | 41017571315 |
10 | 14343403307 |
11 | 60a0528222 |
12 | 29436b074b |
13 | 14777c55bc |
14 | 9a0d47b19 |
15 | 58e367422 |
hex | 356eef72b |
14343403307 has 2 divisors, whose sum is σ = 14343403308. Its totient is φ = 14343403306.
The previous prime is 14343403279. The next prime is 14343403309. The reversal of 14343403307 is 70330434341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14343403307 - 212 = 14343399211 is a prime.
It is a super-3 number, since 3×143434033073 (a number of 31 digits) contains 333 as substring.
Together with 14343403309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14343403309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171701653 + 7171701654.
It is an arithmetic number, because the mean of its divisors is an integer number (7171701654).
Almost surely, 214343403307 is an apocalyptic number.
14343403307 is a deficient number, since it is larger than the sum of its proper divisors (1).
14343403307 is an equidigital number, since it uses as much as digits as its factorization.
14343403307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36288, while the sum is 32.
Adding to 14343403307 its reverse (70330434341), we get a palindrome (84673837648).
The spelling of 14343403307 in words is "fourteen billion, three hundred forty-three million, four hundred three thousand, three hundred seven".
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