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143434353 = 3115341467
BaseRepresentation
bin10001000110010…
…10001001110001
3100222220012221110
420203022021301
5243204344403
622122143533
73361112646
oct1043121161
9328805843
10143434353
1173a68397
1240051ba9
13239405ca
1415099dcd
15c8d4103
hex88ca271

143434353 has 8 divisors (see below), whose sum is σ = 191416288. Its totient is φ = 95537664.

The previous prime is 143434349. The next prime is 143434373. The reversal of 143434353 is 353434341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 143434353 - 22 = 143434349 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 143434353.

It is not an unprimeable number, because it can be changed into a prime (143434373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17275 + ... + 24192.

It is an arithmetic number, because the mean of its divisors is an integer number (23927036).

Almost surely, 2143434353 is an apocalyptic number.

It is an amenable number.

143434353 is a deficient number, since it is larger than the sum of its proper divisors (47981935).

143434353 is a wasteful number, since it uses less digits than its factorization.

143434353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42623.

The product of its digits is 25920, while the sum is 30.

The square root of 143434353 is about 11976.4081844266. The cubic root of 143434353 is about 523.4610752397.

Adding to 143434353 its reverse (353434341), we get a palindrome (496868694).

The spelling of 143434353 in words is "one hundred forty-three million, four hundred thirty-four thousand, three hundred fifty-three".

Divisors: 1 3 1153 3459 41467 124401 47811451 143434353