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143443121 is a prime number
BaseRepresentation
bin10001000110011…
…00010010110001
3100222220122222012
420203030102301
5243210134441
622122252305
73361150343
oct1043142261
9328818865
10143443121
1173a73a38
1240057095
13239445b3
141509d293
15c8d69eb
hex88cc4b1

143443121 has 2 divisors, whose sum is σ = 143443122. Its totient is φ = 143443120.

The previous prime is 143443109. The next prime is 143443159. The reversal of 143443121 is 121344341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128504896 + 14938225 = 11336^2 + 3865^2 .

It is a cyclic number.

It is not a de Polignac number, because 143443121 - 26 = 143443057 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (143443021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71721560 + 71721561.

It is an arithmetic number, because the mean of its divisors is an integer number (71721561).

Almost surely, 2143443121 is an apocalyptic number.

It is an amenable number.

143443121 is a deficient number, since it is larger than the sum of its proper divisors (1).

143443121 is an equidigital number, since it uses as much as digits as its factorization.

143443121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1152, while the sum is 23.

The square root of 143443121 is about 11976.7742318205. The cubic root of 143443121 is about 523.4717412414.

Adding to 143443121 its reverse (121344341), we get a palindrome (264787462).

The spelling of 143443121 in words is "one hundred forty-three million, four hundred forty-three thousand, one hundred twenty-one".