14344321315451 has 2 divisors, whose sum is σ = 14344321315452. Its totient is φ = 14344321315450.

The previous prime is 14344321315433. The next prime is 14344321315453. The reversal of 14344321315451 is 15451312344341.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14344321315451 is a prime.

Together with 14344321315453, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14344321315399 and 14344321315408.

It is not a weakly prime, because it can be changed into another prime (14344321315453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7172160657725 + 7172160657726.

It is an arithmetic number, because the mean of its divisors is an integer number (7172160657726).

Almost surely, 2^{14344321315451} is an apocalyptic number.

14344321315451 is a deficient number, since it is larger than the sum of its proper divisors (1).

14344321315451 is an equidigital number, since it uses as much as digits as its factorization.

14344321315451 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 345600, while the sum is 41.

Adding to 14344321315451 its reverse (15451312344341), we get a palindrome (29795633659792).

The spelling of 14344321315451 in words is "fourteen trillion, three hundred forty-four billion, three hundred twenty-one million, three hundred fifteen thousand, four hundred fifty-one".