Base | Representation |
---|---|
bin | 1000010110010111100… |
… | …0110101110100100100 |
3 | 111201020210220122221021 |
4 | 2011211320311310210 |
5 | 4322232442220400 |
6 | 145521424100524 |
7 | 13235442050263 |
oct | 2054570656444 |
9 | 451223818837 |
10 | 143443320100 |
11 | 5591a018533 |
12 | 23972a64744 |
13 | 106b0074902 |
14 | 6d2aa745da |
15 | 3ae818471a |
hex | 2165e35d24 |
143443320100 has 36 divisors (see below), whose sum is σ = 311305075200. Its totient is φ = 57371232160.
The previous prime is 143443320089. The next prime is 143443320109. The reversal of 143443320100 is 1023344341.
It is a super-2 number, since 2×1434433201002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (143443320109) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 936741 + ... + 1079059.
It is an arithmetic number, because the mean of its divisors is an integer number (8647363200).
Almost surely, 2143443320100 is an apocalyptic number.
143443320100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
143443320100 is an abundant number, since it is smaller than the sum of its proper divisors (167861755100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143443320100 is a wasteful number, since it uses less digits than its factorization.
143443320100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 152412 (or 152405 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 143443320100 its reverse (1023344341), we get a palindrome (144466664441).
The spelling of 143443320100 in words is "one hundred forty-three billion, four hundred forty-three million, three hundred twenty thousand, one hundred".
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