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143489117 is a prime number
BaseRepresentation
bin10001000110101…
…11100001011101
3101000000000001202
420203113201131
5243213122432
622123245245
73361431422
oct1043274135
9330000052
10143489117
1173aa5552
1240079825
132395c505
14150b1d49
15c8e5462
hex88d785d

143489117 has 2 divisors, whose sum is σ = 143489118. Its totient is φ = 143489116.

The previous prime is 143489057. The next prime is 143489119. The reversal of 143489117 is 711984341.

143489117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105801796 + 37687321 = 10286^2 + 6139^2 .

It is a cyclic number.

It is not a de Polignac number, because 143489117 - 214 = 143472733 is a prime.

Together with 143489119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143489119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71744558 + 71744559.

It is an arithmetic number, because the mean of its divisors is an integer number (71744559).

Almost surely, 2143489117 is an apocalyptic number.

It is an amenable number.

143489117 is a deficient number, since it is larger than the sum of its proper divisors (1).

143489117 is an equidigital number, since it uses as much as digits as its factorization.

143489117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24192, while the sum is 38.

The square root of 143489117 is about 11978.6942944546. The cubic root of 143489117 is about 523.5276868384.

The spelling of 143489117 in words is "one hundred forty-three million, four hundred eighty-nine thousand, one hundred seventeen".