Base | Representation |
---|---|
bin | 1000010110100101000… |
… | …1011111110111100111 |
3 | 111201101202210011111001 |
4 | 2011221101133313213 |
5 | 4322342012143211 |
6 | 145531213254131 |
7 | 13240031566321 |
oct | 2055121376747 |
9 | 451352704431 |
10 | 143500115431 |
11 | 5594908a722 |
12 | 23989a94347 |
13 | 106bba6c00a |
14 | 6d3441a611 |
15 | 3aed152ac1 |
hex | 216945fde7 |
143500115431 has 2 divisors, whose sum is σ = 143500115432. Its totient is φ = 143500115430.
The previous prime is 143500115359. The next prime is 143500115459. The reversal of 143500115431 is 134511005341.
It is an a-pointer prime, because the next prime (143500115459) can be obtained adding 143500115431 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143500115431 - 27 = 143500115303 is a prime.
It is a super-2 number, since 2×1435001154312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 143500115431.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143500115831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71750057715 + 71750057716.
It is an arithmetic number, because the mean of its divisors is an integer number (71750057716).
Almost surely, 2143500115431 is an apocalyptic number.
143500115431 is a deficient number, since it is larger than the sum of its proper divisors (1).
143500115431 is an equidigital number, since it uses as much as digits as its factorization.
143500115431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 28.
The spelling of 143500115431 in words is "one hundred forty-three billion, five hundred million, one hundred fifteen thousand, four hundred thirty-one".
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