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143525000219 is a prime number
BaseRepresentation
bin1000010110101011000…
…0011011010000011011
3111201110111121102222212
42011222300123100123
54322414400001334
6145533502505335
713240453241606
oct2055260332033
9451414542885
10143525000219
1155961136a67
122399629524b
13106c3c72943
146d3785733d
153b0041aece
hex216ac1b41b

143525000219 has 2 divisors, whose sum is σ = 143525000220. Its totient is φ = 143525000218.

The previous prime is 143525000191. The next prime is 143525000221. The reversal of 143525000219 is 912000525341.

It is a strong prime.

It is an emirp because it is prime and its reverse (912000525341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143525000219 - 232 = 139230032923 is a prime.

It is a super-2 number, since 2×1435250002192 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 143525000221, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (143525009219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71762500109 + 71762500110.

It is an arithmetic number, because the mean of its divisors is an integer number (71762500110).

Almost surely, 2143525000219 is an apocalyptic number.

143525000219 is a deficient number, since it is larger than the sum of its proper divisors (1).

143525000219 is an equidigital number, since it uses as much as digits as its factorization.

143525000219 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 32.

The spelling of 143525000219 in words is "one hundred forty-three billion, five hundred twenty-five million, two hundred nineteen", and thus it is an aban number.