Base | Representation |
---|---|
bin | 1101000011100001010000… |
… | …1111100000110011111111 |
3 | 1212211020111022202210111211 |
4 | 3100320110033200303333 |
5 | 3340134214300022421 |
6 | 50310105234225251 |
7 | 3011023324352314 |
oct | 320702417406377 |
9 | 55736438683454 |
10 | 14354120314111 |
11 | 4634603784a06 |
12 | 1739b11a25227 |
13 | 80178434ab56 |
14 | 378a59212d0b |
15 | 19d5b4a409e1 |
hex | d0e143e0cff |
14354120314111 has 2 divisors, whose sum is σ = 14354120314112. Its totient is φ = 14354120314110.
The previous prime is 14354120314091. The next prime is 14354120314117. The reversal of 14354120314111 is 11141302145341.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14354120314111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14354120314117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177060157055 + 7177060157056.
It is an arithmetic number, because the mean of its divisors is an integer number (7177060157056).
Almost surely, 214354120314111 is an apocalyptic number.
14354120314111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14354120314111 is an equidigital number, since it uses as much as digits as its factorization.
14354120314111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 14354120314111 its reverse (11141302145341), we get a palindrome (25495422459452).
The spelling of 14354120314111 in words is "fourteen trillion, three hundred fifty-four billion, one hundred twenty million, three hundred fourteen thousand, one hundred eleven".
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