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14354412444517 is a prime number
BaseRepresentation
bin1101000011100010010110…
…1001111001101101100101
31212211021020200110120002111
43100320211221321231211
53340140314041211032
650310154231441021
73011033502414415
oct320704551715545
955737220416074
1014354412444517
1146347436738a2
121739b93826171
138017cca21992
14378a85d38645
1519d5d04e7c47
hexd0e25a79b65

14354412444517 has 2 divisors, whose sum is σ = 14354412444518. Its totient is φ = 14354412444516.

The previous prime is 14354412444499. The next prime is 14354412444529. The reversal of 14354412444517 is 71544421445341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14051297232036 + 303115212481 = 3748506^2 + 550559^2 .

It is a cyclic number.

It is not a de Polignac number, because 14354412444517 - 235 = 14320052706149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14354412444817) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177206222258 + 7177206222259.

It is an arithmetic number, because the mean of its divisors is an integer number (7177206222259).

Almost surely, 214354412444517 is an apocalyptic number.

It is an amenable number.

14354412444517 is a deficient number, since it is larger than the sum of its proper divisors (1).

14354412444517 is an equidigital number, since it uses as much as digits as its factorization.

14354412444517 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4300800, while the sum is 49.

Adding to 14354412444517 its reverse (71544421445341), we get a palindrome (85898833889858).

The spelling of 14354412444517 in words is "fourteen trillion, three hundred fifty-four billion, four hundred twelve million, four hundred forty-four thousand, five hundred seventeen".