Base | Representation |
---|---|
bin | 1101000011100100111101… |
… | …1011000111010010001110 |
3 | 1212211100001112002012000111 |
4 | 3100321033123013102032 |
5 | 3340143232440223042 |
6 | 50310351543350234 |
7 | 3011060042010433 |
oct | 320711733072216 |
9 | 55740045065014 |
10 | 14355113211022 |
11 | 4634a73197071 |
12 | 173a14a45237a |
13 | 8018b1c6bc0c |
14 | 378b11031b8a |
15 | 19d621cbc517 |
hex | d0e4f6c748e |
14355113211022 has 4 divisors (see below), whose sum is σ = 21532669816536. Its totient is φ = 7177556605510.
The previous prime is 14355113211017. The next prime is 14355113211029. The reversal of 14355113211022 is 22011231155341.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14355113211029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3588778302754 + ... + 3588778302757.
It is an arithmetic number, because the mean of its divisors is an integer number (5383167454134).
Almost surely, 214355113211022 is an apocalyptic number.
14355113211022 is a deficient number, since it is larger than the sum of its proper divisors (7177556605514).
14355113211022 is an equidigital number, since it uses as much as digits as its factorization.
14355113211022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7177556605513.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 14355113211022 its reverse (22011231155341), we get a palindrome (36366344366363).
The spelling of 14355113211022 in words is "fourteen trillion, three hundred fifty-five billion, one hundred thirteen million, two hundred eleven thousand, twenty-two".
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