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14355125151253 is a prime number
BaseRepresentation
bin1101000011100101000000…
…1000101010011000010101
31212211100002100112210221021
43100321100020222120111
53340143244014320003
650310353051321141
73011060245340545
oct320712010523025
955740070483837
1014355125151253
114634a79a01a27
12173a1524501b1
138018b458c943
14378b1285d325
1519d622d7a2bd
hexd0e5022a615

14355125151253 has 2 divisors, whose sum is σ = 14355125151254. Its totient is φ = 14355125151252.

The previous prime is 14355125151187. The next prime is 14355125151313. The reversal of 14355125151253 is 35215152155341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12495221080164 + 1859904071089 = 3534858^2 + 1363783^2 .

It is a cyclic number.

It is not a de Polignac number, because 14355125151253 - 213 = 14355125143061 is a prime.

It is a super-2 number, since 2×143551251512532 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14355125151853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177562575626 + 7177562575627.

It is an arithmetic number, because the mean of its divisors is an integer number (7177562575627).

Almost surely, 214355125151253 is an apocalyptic number.

It is an amenable number.

14355125151253 is a deficient number, since it is larger than the sum of its proper divisors (1).

14355125151253 is an equidigital number, since it uses as much as digits as its factorization.

14355125151253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 450000, while the sum is 43.

The spelling of 14355125151253 in words is "fourteen trillion, three hundred fifty-five billion, one hundred twenty-five million, one hundred fifty-one thousand, two hundred fifty-three".