Base | Representation |
---|---|
bin | 1101000100001000101110… |
… | …0110011011010100011111 |
3 | 1212212020211112021222222012 |
4 | 3101002023212123110133 |
5 | 3340322412430303343 |
6 | 50315020302541435 |
7 | 3011546654464622 |
oct | 321021346332437 |
9 | 55766745258865 |
10 | 14364712744223 |
11 | 4639049947486 |
12 | 173bb8929787b |
13 | 8027819b348a |
14 | 379381d0bdb9 |
15 | 19d9d4923718 |
hex | d108b99b51f |
14364712744223 has 2 divisors, whose sum is σ = 14364712744224. Its totient is φ = 14364712744222.
The previous prime is 14364712744181. The next prime is 14364712744241. The reversal of 14364712744223 is 32244721746341.
It is a happy number.
14364712744223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14364712744223 - 230 = 14363639002399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14364712747223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7182356372111 + 7182356372112.
It is an arithmetic number, because the mean of its divisors is an integer number (7182356372112).
Almost surely, 214364712744223 is an apocalyptic number.
14364712744223 is a deficient number, since it is larger than the sum of its proper divisors (1).
14364712744223 is an equidigital number, since it uses as much as digits as its factorization.
14364712744223 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5419008, while the sum is 50.
The spelling of 14364712744223 in words is "fourteen trillion, three hundred sixty-four billion, seven hundred twelve million, seven hundred forty-four thousand, two hundred twenty-three".
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