Base | Representation |
---|---|
bin | 11010110000011101… |
… | …00101011010000011 |
3 | 1101002010111201020100 |
4 | 31120032211122003 |
5 | 213404432321011 |
6 | 10333234213443 |
7 | 1015660335465 |
oct | 153016453203 |
9 | 41063451210 |
10 | 14365120131 |
11 | 610181040a |
12 | 294aa24283 |
13 | 147c15a2ab |
14 | 9a3b9c135 |
15 | 591206d56 |
hex | 3583a5683 |
14365120131 has 6 divisors (see below), whose sum is σ = 20749617980. Its totient is φ = 9576746748.
The previous prime is 14365120129. The next prime is 14365120151. The reversal of 14365120131 is 13102156341.
It is a happy number.
14365120131 is a `hidden beast` number, since 1 + 4 + 3 + 651 + 2 + 0 + 1 + 3 + 1 = 666.
It is not a de Polignac number, because 14365120131 - 21 = 14365120129 is a prime.
It is a super-2 number, since 2×143651201312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14365120095 and 14365120104.
It is not an unprimeable number, because it can be changed into a prime (14365120111) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 798062221 + ... + 798062238.
Almost surely, 214365120131 is an apocalyptic number.
14365120131 is a deficient number, since it is larger than the sum of its proper divisors (6384497849).
14365120131 is a wasteful number, since it uses less digits than its factorization.
14365120131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1596124465 (or 1596124462 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 14365120131 its reverse (13102156341), we get a palindrome (27467276472).
The spelling of 14365120131 in words is "fourteen billion, three hundred sixty-five million, one hundred twenty thousand, one hundred thirty-one".
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