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14378201939 is a prime number
BaseRepresentation
bin11010110010000000…
…11111001101010011
31101010001010100002202
431121000133031103
5213421304430224
610334422433415
71016206462043
oct153100371523
941101110082
1014378201939
116109135a22
12295329286b
131481a8a7ca
149a5805723
1559243ceae
hex35901f353

14378201939 has 2 divisors, whose sum is σ = 14378201940. Its totient is φ = 14378201938.

The previous prime is 14378201921. The next prime is 14378201941. The reversal of 14378201939 is 93910287341.

14378201939 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14378201939 - 212 = 14378197843 is a prime.

It is a super-3 number, since 3×143782019393 (a number of 31 digits) contains 333 as substring.

Together with 14378201941, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14378201893 and 14378201902.

It is not a weakly prime, because it can be changed into another prime (14378201909) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7189100969 + 7189100970.

It is an arithmetic number, because the mean of its divisors is an integer number (7189100970).

Almost surely, 214378201939 is an apocalyptic number.

14378201939 is a deficient number, since it is larger than the sum of its proper divisors (1).

14378201939 is an equidigital number, since it uses as much as digits as its factorization.

14378201939 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 326592, while the sum is 47.

The spelling of 14378201939 in words is "fourteen billion, three hundred seventy-eight million, two hundred one thousand, nine hundred thirty-nine".