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144001303513 is a prime number
BaseRepresentation
bin1000011000011100100…
…1011000001111011001
3111202200200212011021121
42012013021120033121
54324403313203023
6150053035405241
713255325612134
oct2060711301731
9452620764247
10144001303513
1156085a88751
1223aa98b3821
131076b84bb02
146d80c0121b
153b2c152d5d
hex21872583d9

144001303513 has 2 divisors, whose sum is σ = 144001303514. Its totient is φ = 144001303512.

The previous prime is 144001303499. The next prime is 144001303517. The reversal of 144001303513 is 315303100441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76426261209 + 67575042304 = 276453^2 + 259952^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-144001303513 is a prime.

It is a super-2 number, since 2×1440013035132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (144001303517) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72000651756 + 72000651757.

It is an arithmetic number, because the mean of its divisors is an integer number (72000651757).

Almost surely, 2144001303513 is an apocalyptic number.

It is an amenable number.

144001303513 is a deficient number, since it is larger than the sum of its proper divisors (1).

144001303513 is an equidigital number, since it uses as much as digits as its factorization.

144001303513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 144001303513 its reverse (315303100441), we get a palindrome (459304403954).

The spelling of 144001303513 in words is "one hundred forty-four billion, one million, three hundred three thousand, five hundred thirteen".