14401111315319 has 2 divisors, whose sum is σ = 14401111315320. Its totient is φ = 14401111315318.

The previous prime is 14401111315277. The next prime is 14401111315321. The reversal of 14401111315319 is 91351311110441.

It is a strong prime.

It is an emirp because it is prime and its reverse (91351311110441) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14401111315319 is a prime.

It is a super-2 number, since 2×14401111315319² (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 14401111315321, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14401111315919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200555657659 + 7200555657660.

It is an arithmetic number, because the mean of its divisors is an integer number (7200555657660).

Almost surely, 2^{14401111315319} is an apocalyptic number.

14401111315319 is a deficient number, since it is larger than the sum of its proper divisors (1).

14401111315319 is an equidigital number, since it uses as much as digits as its factorization.

14401111315319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 35.

The spelling of 14401111315319 in words is "fourteen trillion, four hundred one billion, one hundred eleven million, three hundred fifteen thousand, three hundred nineteen".