144012133011 has 4 divisors (see below), whose sum is σ = 192016177352. Its totient is φ = 96008088672.

The previous prime is 144012132983. The next prime is 144012133019. The reversal of 144012133011 is 110331210441.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110331210441 = 3 ⋅36777070147.

It is not a de Polignac number, because 144012133011 - 2¹¹ = 144012130963 is a prime.

It is a super-2 number, since 2×144012133011² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144012133019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24002022166 + ... + 24002022171.

It is an arithmetic number, because the mean of its divisors is an integer number (48004044338).

Almost surely, 2^144012133011 is an apocalyptic number.

144012133011 is a deficient number, since it is larger than the sum of its proper divisors (48004044341).

144012133011 is an equidigital number, since it uses as much as digits as its factorization.

144012133011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48004044340.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 144012133011 its reverse (110331210441), we get a palindrome (254343343452).

It can be divided in two parts, 14401 and 2133011, that added together give a palindrome (2147412).

The spelling of 144012133011 in words is "one hundred forty-four billion, twelve million, one hundred thirty-three thousand, eleven".