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144012353 = 712119613
BaseRepresentation
bin10001001010101…
…11010001000001
3101000222120210212
420211113101001
5243331343403
622142403505
73366041042
oct1045272101
9330876725
10144012353
1174322681
1240290595
1323ab3714
14151aa8c9
15c99a4d8
hex8957441

144012353 has 8 divisors (see below), whose sum is σ = 146748096. Its totient is φ = 141296400.

The previous prime is 144012331. The next prime is 144012359. The reversal of 144012353 is 353210441.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 144012353 - 218 = 143750209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (144012359) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10175 + ... + 19787.

It is an arithmetic number, because the mean of its divisors is an integer number (18343512).

Almost surely, 2144012353 is an apocalyptic number.

It is an amenable number.

144012353 is a deficient number, since it is larger than the sum of its proper divisors (2735743).

144012353 is an equidigital number, since it uses as much as digits as its factorization.

144012353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9895.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 144012353 is about 12000.5146972953. The cubic root of 144012353 is about 524.1632663847.

Adding to 144012353 its reverse (353210441), we get a palindrome (497222794).

The spelling of 144012353 in words is "one hundred forty-four million, twelve thousand, three hundred fifty-three".

Divisors: 1 71 211 9613 14981 682523 2028343 144012353