Base | Representation |
---|---|
bin | 10100111101001110100… |
… | …000100011100100101001 |
3 | 12002200020012221001100112 |
4 | 110331032200203210221 |
5 | 142043342041420241 |
6 | 3021330453344105 |
7 | 206021536144001 |
oct | 24751640434451 |
9 | 5080205831315 |
10 | 1440131201321 |
11 | 50583557887a |
12 | 1b3135038035 |
13 | a5a5ac05947 |
14 | 4d9ba3ab001 |
15 | 276db4111eb |
hex | 14f4e823929 |
1440131201321 has 2 divisors, whose sum is σ = 1440131201322. Its totient is φ = 1440131201320.
The previous prime is 1440131201287. The next prime is 1440131201363. The reversal of 1440131201321 is 1231021310441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1222218691600 + 217912509721 = 1105540^2 + 466811^2 .
It is a cyclic number.
It is not a de Polignac number, because 1440131201321 - 214 = 1440131184937 is a prime.
It is not a weakly prime, because it can be changed into another prime (1440131204321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720065600660 + 720065600661.
It is an arithmetic number, because the mean of its divisors is an integer number (720065600661).
Almost surely, 21440131201321 is an apocalyptic number.
It is an amenable number.
1440131201321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1440131201321 is an equidigital number, since it uses as much as digits as its factorization.
1440131201321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1440131201321 its reverse (1231021310441), we get a palindrome (2671152511762).
The spelling of 1440131201321 in words is "one trillion, four hundred forty billion, one hundred thirty-one million, two hundred one thousand, three hundred twenty-one".
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