Base | Representation |
---|---|
bin | 10100111101001110100… |
… | …000100011100100000111 |
3 | 12002200020012221001022021 |
4 | 110331032200203210013 |
5 | 142043342041420122 |
6 | 3021330453344011 |
7 | 206021536143622 |
oct | 24751640434407 |
9 | 5080205831267 |
10 | 1440131201287 |
11 | 505835578849 |
12 | 1b3135038007 |
13 | a5a5ac0591c |
14 | 4d9ba3aadb9 |
15 | 276db4111c7 |
hex | 14f4e823907 |
1440131201287 has 2 divisors, whose sum is σ = 1440131201288. Its totient is φ = 1440131201286.
The previous prime is 1440131201281. The next prime is 1440131201321. The reversal of 1440131201287 is 7821021310441.
It is an a-pointer prime, because the next prime (1440131201321) can be obtained adding 1440131201287 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1440131201287 - 223 = 1440122812679 is a prime.
It is a super-3 number, since 3×14401312012873 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1440131201281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720065600643 + 720065600644.
It is an arithmetic number, because the mean of its divisors is an integer number (720065600644).
Almost surely, 21440131201287 is an apocalyptic number.
1440131201287 is a deficient number, since it is larger than the sum of its proper divisors (1).
1440131201287 is an equidigital number, since it uses as much as digits as its factorization.
1440131201287 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10752, while the sum is 34.
The spelling of 1440131201287 in words is "one trillion, four hundred forty billion, one hundred thirty-one million, two hundred one thousand, two hundred eighty-seven".
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