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1440131201287 is a prime number
BaseRepresentation
bin10100111101001110100…
…000100011100100000111
312002200020012221001022021
4110331032200203210013
5142043342041420122
63021330453344011
7206021536143622
oct24751640434407
95080205831267
101440131201287
11505835578849
121b3135038007
13a5a5ac0591c
144d9ba3aadb9
15276db4111c7
hex14f4e823907

1440131201287 has 2 divisors, whose sum is σ = 1440131201288. Its totient is φ = 1440131201286.

The previous prime is 1440131201281. The next prime is 1440131201321. The reversal of 1440131201287 is 7821021310441.

It is an a-pointer prime, because the next prime (1440131201321) can be obtained adding 1440131201287 to its sum of digits (34).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1440131201287 - 223 = 1440122812679 is a prime.

It is a super-3 number, since 3×14401312012873 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1440131201281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720065600643 + 720065600644.

It is an arithmetic number, because the mean of its divisors is an integer number (720065600644).

Almost surely, 21440131201287 is an apocalyptic number.

1440131201287 is a deficient number, since it is larger than the sum of its proper divisors (1).

1440131201287 is an equidigital number, since it uses as much as digits as its factorization.

1440131201287 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10752, while the sum is 34.

The spelling of 1440131201287 in words is "one trillion, four hundred forty billion, one hundred thirty-one million, two hundred one thousand, two hundred eighty-seven".