1440131211193 has 2 divisors, whose sum is σ = 1440131211194. Its totient is φ = 1440131211192.

The previous prime is 1440131211137. The next prime is 1440131211287. The reversal of 1440131211193 is 3911121310441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 722581602304 + 717549608889 = 850048^2 + 847083^2 .

It is an emirp because it is prime and its reverse (3911121310441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1440131211193 - 2²⁵ = 1440097656761 is a prime.

It is not a weakly prime, because it can be changed into another prime (1440131211133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720065605596 + 720065605597.

It is an arithmetic number, because the mean of its divisors is an integer number (720065605597).

Almost surely, 2^{1440131211193} is an apocalyptic number.

It is an amenable number.

1440131211193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1440131211193 is an equidigital number, since it uses as much as digits as its factorization.

1440131211193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 31.

The spelling of 1440131211193 in words is "one trillion, four hundred forty billion, one hundred thirty-one million, two hundred eleven thousand, one hundred ninety-three".