Base | Representation |
---|---|
bin | 10100111101001110100… |
… | …000100101111110000001 |
3 | 12002200020012221112211002 |
4 | 110331032200211332001 |
5 | 142043342042224022 |
6 | 3021330453501345 |
7 | 206021536214423 |
oct | 24751640457601 |
9 | 5080205845732 |
10 | 1440131211137 |
11 | 505835585193 |
12 | 1b3135041855 |
13 | a5a5ac0a258 |
14 | 4d9ba3b0813 |
15 | 276db414092 |
hex | 14f4e825f81 |
1440131211137 has 2 divisors, whose sum is σ = 1440131211138. Its totient is φ = 1440131211136.
The previous prime is 1440131211133. The next prime is 1440131211193. The reversal of 1440131211137 is 7311121310441.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1382903088961 + 57228122176 = 1175969^2 + 239224^2 .
It is a cyclic number.
It is not a de Polignac number, because 1440131211137 - 22 = 1440131211133 is a prime.
It is not a weakly prime, because it can be changed into another prime (1440131211133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720065605568 + 720065605569.
It is an arithmetic number, because the mean of its divisors is an integer number (720065605569).
Almost surely, 21440131211137 is an apocalyptic number.
It is an amenable number.
1440131211137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1440131211137 is an equidigital number, since it uses as much as digits as its factorization.
1440131211137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 29.
Adding to 1440131211137 its reverse (7311121310441), we get a palindrome (8751252521578).
The spelling of 1440131211137 in words is "one trillion, four hundred forty billion, one hundred thirty-one million, two hundred eleven thousand, one hundred thirty-seven".
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