14402220213 has 4 divisors (see below), whose sum is σ = 19202960288. Its totient is φ = 9601480140.

The previous prime is 14402220197. The next prime is 14402220221. The reversal of 14402220213 is 31202220441.

14402220213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14402220213 - 2⁴ = 14402220197 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14402220213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14402220233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2400370033 + ... + 2400370038.

It is an arithmetic number, because the mean of its divisors is an integer number (4800740072).

Almost surely, 2^14402220213 is an apocalyptic number.

It is an amenable number.

14402220213 is a deficient number, since it is larger than the sum of its proper divisors (4800740075).

14402220213 is an equidigital number, since it uses as much as digits as its factorization.

14402220213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4800740074.

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 14402220213 its reverse (31202220441), we get a palindrome (45604440654).

The spelling of 14402220213 in words is "fourteen billion, four hundred two million, two hundred twenty thousand, two hundred thirteen".