144025117 has 4 divisors (see below), whose sum is σ = 144079936. Its totient is φ = 143970300.

The previous prime is 144025093. The next prime is 144025129. The reversal of 144025117 is 711520441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 711520441 = 43 ⋅16546987.

It is a cyclic number.

It is not a de Polignac number, because 144025117 - 2¹¹ = 144023069 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 144025091 and 144025100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144025157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23259 + ... + 28792.

It is an arithmetic number, because the mean of its divisors is an integer number (36019984).

Almost surely, 2^144025117 is an apocalyptic number.

It is an amenable number.

144025117 is a deficient number, since it is larger than the sum of its proper divisors (54819).

144025117 is an equidigital number, since it uses as much as digits as its factorization.

144025117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54818.

The product of its (nonzero) digits is 1120, while the sum is 25.

The square root of 144025117 is about 12001.0464960353. The cubic root of 144025117 is about 524.1787516820.

Adding to 144025117 its reverse (711520441), we get a palindrome (855545558).

The spelling of 144025117 in words is "one hundred forty-four million, twenty-five thousand, one hundred seventeen".