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144030505114981 is a prime number
BaseRepresentation
bin100000101111111010110111…
…000110000001110101100101
3200212222011220112200122101201
4200233322313012001311211
5122334243433302134411
61230154411155322501
742223601120350402
oct4057726706016545
9625864815618351
10144030505114981
114198aaa32a7241
12141a20b08b0431
13624a031427514
14277d183b9d2a9
15119b86d5e93c1
hex82feb7181d65

144030505114981 has 2 divisors, whose sum is σ = 144030505114982. Its totient is φ = 144030505114980.

The previous prime is 144030505114973. The next prime is 144030505114997. The reversal of 144030505114981 is 189411505030441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124210824390081 + 19819680724900 = 11144991^2 + 4451930^2 .

It is an emirp because it is prime and its reverse (189411505030441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 144030505114981 - 23 = 144030505114973 is a prime.

It is a super-2 number, since 2×1440305051149812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144030505114901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72015252557490 + 72015252557491.

It is an arithmetic number, because the mean of its divisors is an integer number (72015252557491).

Almost surely, 2144030505114981 is an apocalyptic number.

It is an amenable number.

144030505114981 is a deficient number, since it is larger than the sum of its proper divisors (1).

144030505114981 is an equidigital number, since it uses as much as digits as its factorization.

144030505114981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 345600, while the sum is 46.

The spelling of 144030505114981 in words is "one hundred forty-four trillion, thirty billion, five hundred five million, one hundred fourteen thousand, nine hundred eighty-one".