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144030505114997 is a prime number
BaseRepresentation
bin100000101111111010110111…
…000110000001110101110101
3200212222011220112200122102022
4200233322313012001311311
5122334243433302134442
61230154411155322525
742223601120350424
oct4057726706016565
9625864815618368
10144030505114997
114198aaa32a7256
12141a20b08b0445
13624a031427527
14277d183b9d2bb
15119b86d5e93d2
hex82feb7181d75

144030505114997 has 2 divisors, whose sum is σ = 144030505114998. Its totient is φ = 144030505114996.

The previous prime is 144030505114981. The next prime is 144030505115023. The reversal of 144030505114997 is 799411505030441.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124716317181316 + 19314187933681 = 11167646^2 + 4394791^2 .

It is a cyclic number.

It is not a de Polignac number, because 144030505114997 - 24 = 144030505114981 is a prime.

It is a super-3 number, since 3×1440305051149973 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144030505114927) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72015252557498 + 72015252557499.

It is an arithmetic number, because the mean of its divisors is an integer number (72015252557499).

Almost surely, 2144030505114997 is an apocalyptic number.

It is an amenable number.

144030505114997 is a deficient number, since it is larger than the sum of its proper divisors (1).

144030505114997 is an equidigital number, since it uses as much as digits as its factorization.

144030505114997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2721600, while the sum is 53.

The spelling of 144030505114997 in words is "one hundred forty-four trillion, thirty billion, five hundred five million, one hundred fourteen thousand, nine hundred ninety-seven".