Base | Representation |
---|---|
bin | 1101000110010111110001… |
… | …0000011101101110100111 |
3 | 1212222220221111120102211111 |
4 | 3101211330100131232213 |
5 | 3341440032132044333 |
6 | 50344410350045451 |
7 | 3014406331201102 |
oct | 321457420355647 |
9 | 55886844512744 |
10 | 14403110034343 |
11 | 46533631428a8 |
12 | 17475044a9887 |
13 | 8062909c16a4 |
14 | 37b1856bb739 |
15 | 19e9d08734cd |
hex | d197c41dba7 |
14403110034343 has 2 divisors, whose sum is σ = 14403110034344. Its totient is φ = 14403110034342.
The previous prime is 14403110034307. The next prime is 14403110034371. The reversal of 14403110034343 is 34343001130441.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14403110034343 - 29 = 14403110033831 is a prime.
It is a super-2 number, since 2×144031100343432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14403110032343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7201555017171 + 7201555017172.
It is an arithmetic number, because the mean of its divisors is an integer number (7201555017172).
Almost surely, 214403110034343 is an apocalyptic number.
14403110034343 is a deficient number, since it is larger than the sum of its proper divisors (1).
14403110034343 is an equidigital number, since it uses as much as digits as its factorization.
14403110034343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 14403110034343 its reverse (34343001130441), we get a palindrome (48746111164784).
The spelling of 14403110034343 in words is "fourteen trillion, four hundred three billion, one hundred ten million, thirty-four thousand, three hundred forty-three".
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