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1440340413103 is a prime number
BaseRepresentation
bin10100111101011010111…
…110101000101010101111
312002200202210121002222001
4110331122332220222233
5142044304121204403
63021403325433131
7206026656335614
oct24753276505257
95080683532861
101440340413103
11505932682779
121b319310b7a7
13a5a92366ab7
144d9da0aa50b
15276ee989c1d
hex14f5afa8aaf

1440340413103 has 2 divisors, whose sum is σ = 1440340413104. Its totient is φ = 1440340413102.

The previous prime is 1440340413079. The next prime is 1440340413107. The reversal of 1440340413103 is 3013140430441.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (3013140430441) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1440340413103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1440340413107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720170206551 + 720170206552.

It is an arithmetic number, because the mean of its divisors is an integer number (720170206552).

Almost surely, 21440340413103 is an apocalyptic number.

1440340413103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1440340413103 is an equidigital number, since it uses as much as digits as its factorization.

1440340413103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1440340413103 its reverse (3013140430441), we get a palindrome (4453480843544).

The spelling of 1440340413103 in words is "one trillion, four hundred forty billion, three hundred forty million, four hundred thirteen thousand, one hundred three".