Base | Representation |
---|---|
bin | 11010110101000101… |
… | …11110100000000111 |
3 | 1101011211201001010210 |
4 | 31122202332200013 |
5 | 213444412121411 |
6 | 10341144050503 |
7 | 1016642103036 |
oct | 153242764007 |
9 | 41154631123 |
10 | 14404020231 |
11 | 612176a657 |
12 | 295ba63a33 |
13 | 148722a2c3 |
14 | 9a900671d |
15 | 59483cca6 |
hex | 35a8be807 |
14404020231 has 4 divisors (see below), whose sum is σ = 19205360312. Its totient is φ = 9602680152.
The previous prime is 14404020217. The next prime is 14404020233. The reversal of 14404020231 is 13202040441.
14404020231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13202040441 = 3 ⋅4400680147.
It is not a de Polignac number, because 14404020231 - 211 = 14404018183 is a prime.
It is a super-2 number, since 2×144040202312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14404020198 and 14404020207.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14404020233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2400670036 + ... + 2400670041.
It is an arithmetic number, because the mean of its divisors is an integer number (4801340078).
Almost surely, 214404020231 is an apocalyptic number.
14404020231 is a deficient number, since it is larger than the sum of its proper divisors (4801340081).
14404020231 is an equidigital number, since it uses as much as digits as its factorization.
14404020231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4801340080.
The product of its (nonzero) digits is 768, while the sum is 21.
Adding to 14404020231 its reverse (13202040441), we get a palindrome (27606060672).
The spelling of 14404020231 in words is "fourteen billion, four hundred four million, twenty thousand, two hundred thirty-one".
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