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14409801000000 = 26325671271801
BaseRepresentation
bin1101000110110000101100…
…0100011110010001000000
31220000120012210210201012100
43101230023010132101000
53342042233024000000
650351434324430400
73015034205362440
oct321541304362100
956016183721170
1014409801000000
11465618700238a
121748871248400
13806ab8c85673
1437b61c192120
1519ec72e96a00
hexd1b0b11e440

14409801000000 has 1176 divisors, whose sum is σ = 59501278373888. Its totient is φ = 3265920000000.

The previous prime is 14409800999977. The next prime is 14409801000029. The reversal of 14409801000000 is 10890441.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 167 ways as a sum of consecutive naturals, for example, 8000999100 + ... + 8001000900.

Almost surely, 214409801000000 is an apocalyptic number.

14409801000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14409801000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29750639186944).

14409801000000 is an abundant number, since it is smaller than the sum of its proper divisors (45091477373888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14409801000000 is an equidigital number, since it uses as much as digits as its factorization.

14409801000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1983 (or 1945 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 27.

Adding to 14409801000000 its reverse (10890441), we get a palindrome (14409811890441).

The spelling of 14409801000000 in words is "fourteen trillion, four hundred nine billion, eight hundred one million", and thus it is an aban number.