14410134442133 has 4 divisors (see below), whose sum is σ = 14745253847808. Its totient is φ = 14075015036460.

The previous prime is 14410134442129. The next prime is 14410134442159. The reversal of 14410134442133 is 33124443101441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14410134442133 - 2² = 14410134442129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14410134442093 and 14410134442102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14410134442103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167559702773 + ... + 167559702858.

It is an arithmetic number, because the mean of its divisors is an integer number (3686313461952).

Almost surely, 2^{14410134442133} is an apocalyptic number.

It is an amenable number.

14410134442133 is a deficient number, since it is larger than the sum of its proper divisors (335119405675).

14410134442133 is an equidigital number, since it uses as much as digits as its factorization.

14410134442133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 335119405674.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 14410134442133 its reverse (33124443101441), we get a palindrome (47534577543574).

The spelling of 14410134442133 in words is "fourteen trillion, four hundred ten billion, one hundred thirty-four million, four hundred forty-two thousand, one hundred thirty-three".