Base | Representation |
---|---|
bin | 1000011000110101010… |
… | …1000111010110001101 |
3 | 111202221221001200120110 |
4 | 2012031111013112031 |
5 | 4330111342341331 |
6 | 150111223110233 |
7 | 13261025441460 |
oct | 2061525072615 |
9 | 452857050513 |
10 | 144105043341 |
11 | 561295a3a46 |
12 | 23b185a2379 |
13 | 107871a191c |
14 | 6d908c72d7 |
15 | 3b362e5946 |
hex | 218d54758d |
144105043341 has 32 divisors (see below), whose sum is σ = 230027747328. Its totient is φ = 78458941440.
The previous prime is 144105043339. The next prime is 144105043351. The reversal of 144105043341 is 143340501441.
It is not a de Polignac number, because 144105043341 - 21 = 144105043339 is a prime.
It is a super-2 number, since 2×1441050433412 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 144105043299 and 144105043308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (144105043321) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 456325 + ... + 704586.
It is an arithmetic number, because the mean of its divisors is an integer number (7188367104).
Almost surely, 2144105043341 is an apocalyptic number.
It is an amenable number.
144105043341 is a deficient number, since it is larger than the sum of its proper divisors (85922703987).
144105043341 is a wasteful number, since it uses less digits than its factorization.
144105043341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1161201.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 144105043341 its reverse (143340501441), we get a palindrome (287445544782).
The spelling of 144105043341 in words is "one hundred forty-four billion, one hundred five million, forty-three thousand, three hundred forty-one".
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