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144107041135 = 529993841663
BaseRepresentation
bin1000011000110101110…
…0101111000101101111
3111202222001211012000211
42012031130233011233
54330112400304020
6150111334003251
713261051432111
oct2061534570557
9452861735024
10144107041135
115612a738a12
1223b191a6527
1310787721055
146d90c873b1
153b3658c85a
hex218d72f16f

144107041135 has 8 divisors (see below), whose sum is σ = 178891499520. Its totient is φ = 111310266144.

The previous prime is 144107041129. The next prime is 144107041153. The reversal of 144107041135 is 531140701441.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 144107041135 - 213 = 144107032943 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 144107041097 and 144107041106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 496920687 + ... + 496920976.

It is an arithmetic number, because the mean of its divisors is an integer number (22361437440).

Almost surely, 2144107041135 is an apocalyptic number.

144107041135 is a deficient number, since it is larger than the sum of its proper divisors (34784458385).

144107041135 is an equidigital number, since it uses as much as digits as its factorization.

144107041135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 993841697.

The product of its (nonzero) digits is 6720, while the sum is 31.

Adding to 144107041135 its reverse (531140701441), we get a palindrome (675247742576).

The spelling of 144107041135 in words is "one hundred forty-four billion, one hundred seven million, forty-one thousand, one hundred thirty-five".

Divisors: 1 5 29 145 993841663 4969208315 28821408227 144107041135