14412204035 has 4 divisors (see below), whose sum is σ = 17294644848. Its totient is φ = 11529763224.

The previous prime is 14412204029. The next prime is 14412204043. The reversal of 14412204035 is 53040221441.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53040221441 = 53129 ⋅998329.

It is a cyclic number.

It is not a de Polignac number, because 14412204035 - 2¹⁴ = 14412187651 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14412203995 and 14412204013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1441220399 + ... + 1441220408.

It is an arithmetic number, because the mean of its divisors is an integer number (4323661212).

Almost surely, 2^14412204035 is an apocalyptic number.

14412204035 is a deficient number, since it is larger than the sum of its proper divisors (2882440813).

14412204035 is an equidigital number, since it uses as much as digits as its factorization.

14412204035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2882440812.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 14412204035 its reverse (53040221441), we get a palindrome (67452425476).

The spelling of 14412204035 in words is "fourteen billion, four hundred twelve million, two hundred four thousand, thirty-five".