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14412413335 = 52882482667
BaseRepresentation
bin11010110110000101…
…11111100110010111
31101012102111110022111
431123002333212113
5214004034211320
610342044011451
71020103330525
oct153302774627
941172443274
1014412413335
116126482501
122962830b87
131488ba8638
149aa18d315
15595449a5a
hex35b0bf997

14412413335 has 4 divisors (see below), whose sum is σ = 17294896008. Its totient is φ = 11529930664.

The previous prime is 14412413293. The next prime is 14412413347. The reversal of 14412413335 is 53331421441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14412413335 - 211 = 14412411287 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14412413297 and 14412413306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1441241329 + ... + 1441241338.

It is an arithmetic number, because the mean of its divisors is an integer number (4323724002).

Almost surely, 214412413335 is an apocalyptic number.

14412413335 is a deficient number, since it is larger than the sum of its proper divisors (2882482673).

14412413335 is an equidigital number, since it uses as much as digits as its factorization.

14412413335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2882482672.

The product of its digits is 17280, while the sum is 31.

Adding to 14412413335 its reverse (53331421441), we get a palindrome (67743834776).

The spelling of 14412413335 in words is "fourteen billion, four hundred twelve million, four hundred thirteen thousand, three hundred thirty-five".

Divisors: 1 5 2882482667 14412413335