Base | Representation |
---|---|
bin | 11010110110000101… |
… | …11111100110010111 |
3 | 1101012102111110022111 |
4 | 31123002333212113 |
5 | 214004034211320 |
6 | 10342044011451 |
7 | 1020103330525 |
oct | 153302774627 |
9 | 41172443274 |
10 | 14412413335 |
11 | 6126482501 |
12 | 2962830b87 |
13 | 1488ba8638 |
14 | 9aa18d315 |
15 | 595449a5a |
hex | 35b0bf997 |
14412413335 has 4 divisors (see below), whose sum is σ = 17294896008. Its totient is φ = 11529930664.
The previous prime is 14412413293. The next prime is 14412413347. The reversal of 14412413335 is 53331421441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14412413335 - 211 = 14412411287 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14412413297 and 14412413306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1441241329 + ... + 1441241338.
It is an arithmetic number, because the mean of its divisors is an integer number (4323724002).
Almost surely, 214412413335 is an apocalyptic number.
14412413335 is a deficient number, since it is larger than the sum of its proper divisors (2882482673).
14412413335 is an equidigital number, since it uses as much as digits as its factorization.
14412413335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2882482672.
The product of its digits is 17280, while the sum is 31.
Adding to 14412413335 its reverse (53331421441), we get a palindrome (67743834776).
The spelling of 14412413335 in words is "fourteen billion, four hundred twelve million, four hundred thirteen thousand, three hundred thirty-five".
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