Base | Representation |
---|---|
bin | 1101000110111101110001… |
… | …1011110000101101111011 |
3 | 1220000220021121021101101211 |
4 | 3101233130123300231323 |
5 | 3342121431231334120 |
6 | 50353215042423551 |
7 | 3015220226452621 |
oct | 321573433605573 |
9 | 56026247241354 |
10 | 14413313543035 |
11 | 4657719816a10 |
12 | 1749491661bb7 |
13 | 8072288c41b4 |
14 | 37b872897511 |
15 | 19edcb53025a |
hex | d1bdc6f0b7b |
14413313543035 has 8 divisors (see below), whose sum is σ = 18868337729136. Its totient is φ = 10482409849440.
The previous prime is 14413313543003. The next prime is 14413313543047. The reversal of 14413313543035 is 53034531331441.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14413313543035 - 25 = 14413313543003 is a prime.
It is a super-2 number, since 2×144133135430352 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 131030123064 + ... + 131030123173.
It is an arithmetic number, because the mean of its divisors is an integer number (2358542216142).
Almost surely, 214413313543035 is an apocalyptic number.
14413313543035 is a deficient number, since it is larger than the sum of its proper divisors (4455024186101).
14413313543035 is a wasteful number, since it uses less digits than its factorization.
14413313543035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 262060246253.
The product of its (nonzero) digits is 388800, while the sum is 40.
Adding to 14413313543035 its reverse (53034531331441), we get a palindrome (67447844874476).
The spelling of 14413313543035 in words is "fourteen trillion, four hundred thirteen billion, three hundred thirteen million, five hundred forty-three thousand, thirty-five".
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