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14414310131 = 131108793087
BaseRepresentation
bin11010110110010100…
…01110101011110011
31101012120001211020012
431123022032223303
5214010030411011
610342152405135
71020125420534
oct153312165363
941176054205
1014414310131
116127558601
1229633a67ab
1314893c0ac0
149aa52468b
155956c1a8b
hex35b28eaf3

14414310131 has 4 divisors (see below), whose sum is σ = 15523103232. Its totient is φ = 13305517032.

The previous prime is 14414310109. The next prime is 14414310161. The reversal of 14414310131 is 13101341441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14414310131 - 26 = 14414310067 is a prime.

It is a super-2 number, since 2×144143101312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14414310097 and 14414310106.

It is not an unprimeable number, because it can be changed into a prime (14414310161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 554396531 + ... + 554396556.

It is an arithmetic number, because the mean of its divisors is an integer number (3880775808).

Almost surely, 214414310131 is an apocalyptic number.

14414310131 is a deficient number, since it is larger than the sum of its proper divisors (1108793101).

14414310131 is a wasteful number, since it uses less digits than its factorization.

14414310131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1108793100.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 14414310131 its reverse (13101341441), we get a palindrome (27515651572).

The spelling of 14414310131 in words is "fourteen billion, four hundred fourteen million, three hundred ten thousand, one hundred thirty-one".

Divisors: 1 13 1108793087 14414310131