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14420131421 is a prime number
BaseRepresentation
bin11010110111000000…
…11011111001011101
31101012222000120112112
431123200123321131
5214013023201141
610342521243405
71020226044323
oct153340337135
941188016475
1014420131421
11612a874193
122965333565
13148a67b657
149ab1dbd13
15595e717eb
hex35b81be5d

14420131421 has 2 divisors, whose sum is σ = 14420131422. Its totient is φ = 14420131420.

The previous prime is 14420131379. The next prime is 14420131433. The reversal of 14420131421 is 12413102441.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13125139225 + 1294992196 = 114565^2 + 35986^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14420131421 is a prime.

It is a super-2 number, since 2×144201314212 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14420131021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7210065710 + 7210065711.

It is an arithmetic number, because the mean of its divisors is an integer number (7210065711).

Almost surely, 214420131421 is an apocalyptic number.

It is an amenable number.

14420131421 is a deficient number, since it is larger than the sum of its proper divisors (1).

14420131421 is an equidigital number, since it uses as much as digits as its factorization.

14420131421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 14420131421 its reverse (12413102441), we get a palindrome (26833233862).

The spelling of 14420131421 in words is "fourteen billion, four hundred twenty million, one hundred thirty-one thousand, four hundred twenty-one".